内容纲要

1.用选择法对十个整数排序

#include<iostream>
using namespace std ;
int numbers[10];
void ascending();
void Cins();
void couts();
void main()
{
    Cins();
    ascending();
    couts();
    system("pause");
}
void ascending()
{
    int x=0;
    int y = 0;
    int z ;
    for(int i=0+x;i<=9;i++)
    {
        for (int v=1+y;v<=9;v++)
        {
            if (numbers[i]>=numbers[v])
            {
                z = numbers[i];
                numbers[i] = numbers[v];
                numbers[v] = z;
            }
        }
        x++;
        y++;
    }
}
void Cins()
{
    for (int i=0;i<=9;i++)
    {
        cout << "输入第" << i + 1 << "个数字;" << endl;
        cin >> numbers[i];
    }
}
void couts()
{
    for (int i=0;i<=9;i++)
    {
        cout<< numbers[i] <<endl;
    }
}

2.求一个3*3对角线的元素之和

#include <iostream>
using namespace std;
void countNumbers(int x);
void cins();
int  a[3][3];
int b[3];
void main()
{
    cins();
    countNumbers(3);
    system("pause");
}
void countNumbers(int x)//决定数组长度,仅限于有长度的数组;
{

    for(int i=0;i<x;i++)
    {
        b[i] = a[i][i] + a[i][x - 1 - i];
    }
    for(int s=1;s<=x-1;s++)
    {
        b[s] = b[s-1] + b[s];
    }
    cout << b[x-1] << endl;
}
void cins()
{
    for (int d=0;d<3;d++)
    {
        for (int w=0;w<3;w++)
        {
            cout << "请输入"<<d <<w<< "字符;"<< endl;
            cin >> a[d][w];
        }
    }
}

输出结果
c++基础第五章课后练习第二部分插图

3.有一个已经排序好的数组,现在输入一个数,按照原来的规律插入数组

#include<iostream>
using namespace std;
int numbers[11];
void ascending(int NumbersLongs);
void Cins();
void couts();
void CinTwo();
int NumbersLong=9;
void main()
{
    Cins();
    ascending(9);
    couts();
    CinTwo();
    system("pause");
}
void ascending(int NumbersLongs)
{
    NumbersLong = NumbersLongs;
    int x = 0;
    int y = 0;
    int z;
    for (int i = 0 + x; i <= NumbersLongs; i++)
    {
        for (int v = 1 + y; v <= NumbersLongs; v++)
        {
            if (numbers[i] >= numbers[v])
            {
                z = numbers[i];
                numbers[i] = numbers[v];
                numbers[v] = z;
            }
        }
        x++;
        y++;
    }
}
void Cins()
{
    for (int i = 0; i <= NumbersLong; i++)
    {
        cout << "输入第" << i + 1 << "个数字;" << endl;
        cin >> numbers[i];
    }
}
void couts()
{
    for (int i = 0; i <= NumbersLong; i++)
    {
        cout << numbers[i] << endl;
    }
}
void CinTwo()//新输入数字排序输出;
{
    cout << "输入一个新数字;" << endl;
    cin >> numbers[10];//添加入已经排序好的数组;
    ++NumbersLong;
    cout << "新的排序" << endl;
    ascending(10);
    couts();

}

4.将一个数组值按照逆顺序重新存放

#include <iostream>
using namespace std;
int a[6] ;
void Cins();
void count(int p);
void Coutss();
void main()
{
    Cins();
    count(6);
    Coutss();
    system("pause");
}
void count(int p)
{
    int x=0;
    for (int i=0;i<=2/p;i++)//
    {
            x = a[i];
            a[i] = a[p - i - 1];
            a[p - i - 1] = x;
    }
}
void Cins()
{
    for (int i=0;i<=5;i++)
    {
        cin >>a[i];
    }
}
void Coutss()
{
    for (int e = 0; e <= 5; e++)
    {
        cout << a[e] << endl;
    }
}

3 对 “c++基础第五章课后练习第二部分”的想法;

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    In this mail sending you special our offer about immigration services to Europe:
    1. Work 1 Year Visa to Poland (Work Visa+Work Permit);
    2. Study in Poland (Study 1 Year Visa);
    3. Business Immigration to Poland (Business 1 Year Visa);
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    If you are interesting in our services, please contact with us in WhatsUp/Viber/Telegram +48 793 636 986 or write me: r.kowalski@legalpl.net
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